x^2-19x+81=0

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Solution for x^2-19x+81=0 equation: 



x^2-19x+81=0

a = 1; b = -19; c = +81;
Δ = b2-4ac
Δ = -192-4·1·81
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{37}}{2*1}=\frac{19-\sqrt{37}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{37}}{2*1}=\frac{19+\sqrt{37}}{2}
$

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